in.add()
[3124] 최소 스패닝 트리 본문
SW Expert Academy
SW 프로그래밍 역량 강화에 도움이 되는 다양한 학습 컨텐츠를 확인하세요!
swexpertacademy.com
문제 해결 방법
크루스칼 알고리즘을 사용했다.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.PriorityQueue;
import java.util.StringTokenizer;
public class Solution {
static int V, E;
static int[] parent;
static PriorityQueue<Node> q;
static class Node {
int from;
int to;
int cost;
public Node(int from, int to, int cost) {
this.from = from;
this.to = to;
this.cost = cost;
}
}
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
for (int t = 1; t <= T; t++) {
StringTokenizer st = new StringTokenizer(br.readLine(), " ");
V = Integer.parseInt(st.nextToken());
E = Integer.parseInt(st.nextToken());
long answer = 0;
parent = new int[V + 1];
q = new PriorityQueue<>((n1, n2) -> n1.cost - n2.cost);
for (int i = 0; i <= V; i++) {
parent[i] = i;
}
for (int i = 0; i < E; i++) {
st = new StringTokenizer(br.readLine(), " ");
q.add(new Node(Integer.parseInt(st.nextToken()), Integer.parseInt(st.nextToken()), Integer.parseInt(st.nextToken())));
}
while (!q.isEmpty()) {
Node n = q.poll();
if (find(n.from) != find(n.to)) {
union(n.from, n.to);
answer += n.cost;
}
}
System.out.println("#" + t + " " + answer);
}
}
private static void union(int from, int to) {
int parentFrom = find(from);
int parentTo = find(to);
parent[parentTo] = parentFrom;
}
private static int find(int num) {
if (parent[num] == num) {
return num;
} else return parent[num] = find(parent[num]);
}
}
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